Bypass CUSTOMER_LOGIN_NOT_VALID_FOR_TIME and CUSTOMER_NO_VALID_PRODUCT Validation
(Doc ID 2121306.1)
Last updated on FEBRUARY 24, 2022
Applies to:Oracle Communications Billing and Revenue Management - Version 22.214.171.124.0 and later
Information in this document applies to any platform.
On : 126.96.36.199.0 version, Pipeline Manager
How to configure the Pipeline Rating to bypass the ERR_CUSTOMER_LOGIN_NOT_VALID_FOR_TIME and ERR_CUSTOMER_NO_VALID_PRODUCT validation?
Regardless of the account being inactivated or not, EDR needs to be rated, recycled, and billed.
The user has tested with these registry entries:
FCT_Account.UseAsRouter False as default.
But, the EDR was still been rejected with empty error message:
31.08.2015 14:22:09 The actual log level is Debug. All messages with this or higher severity will be logged.
31.08.2015 14:22:09 Beginning to process stream 'RAT_XXXXXXX1.GRD2424.D17082015.H155042.brm'.
31.08.2015 14:22:09 The EDR with number '00000001' (starting at byteposition:119) contains the errors :
31.08.2015 14:22:09 The EDR is rejected.
31.08.2015 14:22:09 End of the processing of stream 'RAT_XXXXXXX1.GRD2424.D17082015.H155042.brm'
When a new product with "rate even if cancelled, inactive" configuration got created, BRM rated the event even the account was inactive/cancelled correctly.
But, there seemed no way to change the configuration of pre-existing products. After changing the flag in Pricing Center and committing it to BRM Database, there was the error:
ORA-00001: unique constraint (PIN.I_PRODUCT__NAME) violated.
In fact, as per database, this product was identified as the following:
1 PIN_FLD_NAME STR  "XXXXXX PME XXXXXXXX RP - 022113 - VCM:300.00 v2"
1 PIN_FLD_CODE STR  "XXXXXX PME XXXXXXXXXXXXX RP - 020242 -VCM: 139.90 v1(9)".
There were a few more products with different values between PIN_FLD_NAME and PIN_FLD_CODE. No customization in Pricing Center and the SET_PRICE_LIST opcode was invoked manually through it.
Should PIN_FLD_CODE not persist with the previous PIN_FLD_CODE? Should it not be unique?
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