How do you create a custom Workflow and get it to appear under the 'Identifier' column in Define Approval Style Form?
(Doc ID 338758.1)
Last updated on JULY 17, 2019
Applies to:Oracle Time and Labor - Version 11.5.10 to 12.1.3 [Release 11.5 to 12.1]
Information in this document applies to any platform.
***Checked for relevance on 14-MAR-2016***
***Checked for relevance on 23-NOV-2010***
You are attempting to define an approval style using the Workflow type. In the Approval Style form you entered:
Application = Projects
Type = Workflow
And do not get any values under Identifier column LOV
Documentation talks about sample wf - HXCSAW
However you are unable to find any wf with that wf type. The only OTL wf is HXCEMP. You created a skeleton wf (start, end) to be able to save in the db. You verified and saved it into database, and are still unable to select wf in identifier column.
Why can't you see this new Workflow value in the Identifier column?
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